4[d-4]+2=3[d+1]

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Solution for 4[d-4]+2=3[d+1] equation:


Simplifying
4[d + -4] + 2 = 3[d + 1]

Reorder the terms:
4[-4 + d] + 2 = 3[d + 1]
[-4 * 4 + d * 4] + 2 = 3[d + 1]
[-16 + 4d] + 2 = 3[d + 1]

Reorder the terms:
-16 + 2 + 4d = 3[d + 1]

Combine like terms: -16 + 2 = -14
-14 + 4d = 3[d + 1]

Reorder the terms:
-14 + 4d = 3[1 + d]
-14 + 4d = [1 * 3 + d * 3]
-14 + 4d = [3 + 3d]

Solving
-14 + 4d = 3 + 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
-14 + 4d + -3d = 3 + 3d + -3d

Combine like terms: 4d + -3d = 1d
-14 + 1d = 3 + 3d + -3d

Combine like terms: 3d + -3d = 0
-14 + 1d = 3 + 0
-14 + 1d = 3

Add '14' to each side of the equation.
-14 + 14 + 1d = 3 + 14

Combine like terms: -14 + 14 = 0
0 + 1d = 3 + 14
1d = 3 + 14

Combine like terms: 3 + 14 = 17
1d = 17

Divide each side by '1'.
d = 17

Simplifying
d = 17

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